CTET 2 Math and Science Jul 2013 Paper

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Question : 60 of 120

Marks: +1, -0

If

\;\;{2}/{3},\;\;{23}/{30},\;\;{9}/{10},\;\;{11}/{15}

and

4 / 5

are written in ascending order, then the fraction in the middle most will be

$23 / 30$
$4 / 5$
$2 / 3$
$11 / 15$

Solution:

LCM of 3, 30, 10, 15 and

5=30

\;\;{2×10}/{3×10}=\;\;{20}/{30},\;\;{23}/{30},\;\;{9×3}/{10×3}=\;\;{27}/{30},\;\;{11×2}/{15×2}=\;\;{22}/{30},\;\;{4×6}/{5×6}=\;\;{24}/{30}

Ascending order

\;\;{20}/{30},\;\;{22}/{30},\;\;{23}/{30},\;\;{24}/{30},\;\;{27}/{30}

⇒\;\;{2}/{3},\;\;{11}/{15},\;\;{23}/{30},\;\;{4}/{5},\;\;{9}/{10}

∴ The fraction in the middle

=23/30

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