CTET 2 Math and Science Jan 2012 Paper

Question : 43 of 120

Marks: +1, -0

When the number

3^98

is divided by 5, the remainder is

Solution:

3^98

3^1=3

3^2=9

3^3=7

3^4=1

3^5=3

Hence unit digit repeat after 4

\;\;{98}/{4}=24\;\;{2}/{4}

means Remainder is 2 unit digit of

3^98=3^2=9

9/5

then, we get 4 as a remainder

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