CTET 2 Math and Science Jan 2012 Paper

Question : 36 of 120

Marks: +1, -0

Given n numbers,

n > 1

, of which, one is

1-1/n^2

and all other are 1's. The mean of then n numbers is

Solution:

\Mean=\;\;{(n-1)+(1-\;\;{1}/{n})}/{n}=\;\;{n-\;\;{1}/{n}}/{n}=1-\;\;{1}/{n^{2}}

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