CTET 2 Math and Science Jan 2012 Paper

Question : 33 of 120

Marks: +1, -0

The mean of the median, mode and range the observations6, 6, 9, 14, 8, 9, 9, 8 is

$10.5$
$8.5$
$8.8$
$10.3$

Solution:

Given numbers are
6, 6, 9, 14, 8, 9, 9, 8
Arranging in ascending order
6, 6, 8, 8, 9, 9, 9, 1
Range = maximum – minimum = 14 – 6 = 8
Mode = 9 (the no. that occurs maximum times)

\Median=\;\;{8+9}/{2}=8.5

\text "Required mean"=\;\;{\;\text"Range"\;+\;\text"Mode"\;+\;\text"Median"\;}/{3}=\;\;{8+9+8.5}/{3}=8.5

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