CTET 2 Math and Science Feb 2016 Paper

Question : 38 of 120

Marks: +1, -0

If AB × BA = BCB, where A, B and C stand for just one digit and A ≠ B ≠ C, then the value of A + B + C is

Solution:

According to the option
AB × BA = BCB

12×21=252

∴A=1,B=2 and C=5

∴A+B+C=1+2+5=8

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