CTET 2 Math and Science Feb 2016 Paper

Question : 33 of 120

Marks: +1, -0

Let

x = 597 × 10^22 + 73.5 × 10^21

. When x is expressed in standard form as

6.0435 × 10^m

, then the value of m is

Solution:

x=597×10^{22}+73.5×10^{21}

According to the question

597×10^{22}+73.5×10^{21}=6.0435×10^{{m}}

⇒597×10×10^{21}+73.5×10^{21}=6.0435×10^{m}

⇒10^{21}(5970+73.5)=6.0435×10^{{m}}

⇒10^{21}(6043.5)=6.0435×10^{{m}}

⇒10^{21}×10^{3}×6.0435=6.0435×10^{{m}}

⇒10^{{m}}=10^{24}

∴m=24

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