What is the value of A such that \sqrt^3{500} \times \sqrt ^{3}{-3456} = 40 \times A is true?

CTET 2 Math and Science Feb 2016 Paper

Question : 31 of 120

Marks: +1, -0

What is the value of A such that

√^3{500} × √ ^{3}{-3456} = 40 × A

is true?

Solution:

√^3{500}×√^3{-3456}=40×A

⇒40A=√^3{500×(-3456)}

⇒40A=√^3{(5)^{3}×2×2×(-12)^{3}×2}

⇒40A=5×2×(-12)

∴A=\;\;{-120}/{40}=-3

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