CTET 2 Math and Science Feb 2014 Paper

Question : 50 of 120

Marks: +1, -0

The mean of median and mode of the data 7, 6, 7, 9, 8, 8, 10, 8 is

Solution:

On arranging of data
6, 7, 7 ,8, 8, 8, 9, 10

∴x=8

that is even

∴=\;\;{(\;\;{{x}}/{2})^{{th}}\;\text"observation"\;(\;\;{{x}}/{2}+1)^{{th}}\;\text"obs."\;}/{2}

=\;\;{(\;\;{8}/{2})^{{th}}\;\text"obser."\;+(\;\;{8}/{2}+1)^{{th}}\;\text"obs."\;}/{2}

=\;\;{4^{\;\text"th"\;}\;\text"observation"\;+5^{\;\text"th"\;}\;\text"observation"\;}/{2}

=\;\;{8+8}/{2}=\;\;{16}/{2}=8

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