CTET 2 Math and Science Feb 2014 Paper

Question : 33 of 120

Marks: +1, -0

a^3 =1 + 7

3^3 = l + 7 + b

and

4^3 = 1 + 7 + c

, where a, b and c are different positive integers, then the value of a + b + c is

Solution:

a^3=1+7

a^3=8

a=2

3^{3}=1+7+{b}

27-8={b}

{b}=19

4^{3}=1+7+{c}

64-8=c

c=56

Now

a+b+c=2+19+56=77

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