CTET 2 Math and Science Dec 2019 Paper

Question : 45 of 120

Marks: +1, -0

What is the value of

a(a + b^2 + c) + b^2(a^2

+ b^2 + c^2) - c(a + b^2)

, when

a = 1, b = -3

and

c = -2

Solution:

When, a = 1, b = –3 and c = –2
Then,

a(a + b^ 2 + c)

+ b^ 2 (a^ 2 + b^ 2 + c^ 2 )

- c(a + b^ 2 )

= 1[1 + (-3)^2 + (-2)] + (-3)^2 [12 + (-3)^2 + (-2)^2 ] - (-2)[1 + (-3)^2 ]

= (1 + 9 – 2) + 9(1 + 9 + 4) + 2(1 + 9)
= 8 + 9(14) + 2(10)
= 8 + 126 + 20
= 134 + 20 = 154.

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