CTET 2 Math and Science Dec 2019 Paper

Let A, B and C gets x, y and z respectively
According to the question,
4x = 6y = 9z ...(i)
From (i), we get $\mathit{y}=\frac{2}{3}\mathit{x}$ and $\mathit{z}=\frac{4}{9}\mathit{x}$
Again, x + y + z = 1710
$\Rightarrow \left(\frac{9+6+4}{9}\right)\mathit{x}=1710$
$\Rightarrow \frac{19}{9}\mathit{x}=1710$
$\Rightarrow \mathit{x}=810$
$\mathit{z}=\frac{4}{9}\times 810=360$
Difference between A and C = x – z = 810 – 360 = ₹ 450.