\frac{1+x+x y+x^2 y}{3+2 x-x^2} is equal to

CTET 2 Math and Science 23 Dec 2021 Paper

Question : 42 of 151

Marks: +1, -0

\;{1+x+x y+x^2 y}/{3+2 x-x^2}

is equal to

Solution:

\;{1+x+x y+x^2 y}/{3+2 x-x^2}

⇒ \;{1(1+x)+x y(1+x)}/{-x^2+3 x-x+3}

⇒ \;{(1+x)(1+x y)}/{-(1+x)(x-3)}

∴ \;{(1+x y)}/{(-x+3)}

The correct option is 2 i.e.

\;{1+x y}/{3-x}

Go to Question:

Prev Question

Next Question