CTET 2 Math and Science 21 Jan 2024 Paper

Let's denote the three consecutive integers as $\mathit{x},\mathit{x}+1$, and $\mathit{x}+2$.
According to the given conditions:
$3\mathit{x}$ is the result when the first integer is multiplied by 3 .
$5\left(\mathit{x}+1\right)$ is the result when the second integer is multiplied by 5 .
$2\left(\mathit{x}+2\right)$ is the result when the third integer is multiplied by 2 .
The sum of these results is 99 :
$3\times \mathit{x}+5\times \left(\mathit{x}+1\right)+2\times \left(\mathit{x}+2\right)=99$
Now, let's solve this equation:
$3\mathit{x}+5\mathit{x}+5+2\mathit{x}+4=99$
$10\mathit{x}+9=99$
$10\mathit{x}=90$
$\mathit{x}=9$
So, the three consecutive integers are 9,10 , and 11 .
Now, the sum of the original first and third integers is $9+11=20$.