CTET 2 Math and Science 21 Jan 2024 Paper

Circumference of Circle $=2\times \mathit{\pi }\times \mathit{r}$ where, r is the radius.
Curved Surface Area of Cylinder $=2\mathit{\pi }\mathit{r}\mathit{h}$
Volume of Cylinder $=\mathit{\pi }{\mathit{r}}^2\mathit{h}$ where $\mathit{r}$ is the radius and $\mathit{h}$ is the height of Cylinder.
Explanation:
Curved surface area $=4400\mathit{c}{\mathit{m}}^2$
Circumference of the base $=110\mathit{c}\mathit{m}$
$\mathit{\pi }=22∕7$
Circumference $=2\mathit{\pi }\mathit{r}$
$110=2\times \left(22∕7\right)\times \mathit{r}$
$\mathit{r}=110\times 7∕\left(2\times 22\right)=17.5\mathit{c}\mathit{m}$
Now,
Curved surface area $=2\mathit{\pi }\mathit{r}\mathit{h}$
$4400=2\times \left(22∕7\right)\times 17.5\times \mathit{h}$
$\mathit{h}=4400\times 7∕\left(2\times 22\times 17.5\right)=40\mathit{c}\mathit{m}$
Volume $=\mathit{\pi }{\mathit{r}}^2\mathit{h}$
Volume $=\left(22∕7\right)\times {\left(17.5\right)}^2\times 40$
Volume $=38500\mathit{c}{\mathit{m}}^3$
Volume $=0.0385{\mathit{m}}^3$
Therefore, the volume of the right circular cylinder is $0.0385{\mathit{m}}^3$.