CTET 2 Math and Science 07 Jul 2024 Paper

A is the amount after 2 years $=3267$
r is the rate of interest $=10\%$
n is the number of years $=2$ years
Concept Used:
$\mathit{A}=\mathit{P}{\left(1+\frac{\mathit{r}}{100}\right)}^2$
$\mathit{S}.\mathit{I}=\frac{\mathit{p}\times \mathit{r}\times \mathit{t}}{100}$
Calculation:
Determine the principal amount
$\mathit{A}=\mathit{P}{\left(1+\frac{\mathit{r}}{100}\right)}^2$
$\Rightarrow 3267=\mathit{P}{\left(1+10∕100\right)}^2$
$\Rightarrow \mathit{P}=3267\times 100∕110\times 100∕110=2700$
Now Simple Interest
$\mathit{S}.\mathit{I}=\frac{\mathit{p}\times \mathit{r}\times \mathit{t}}{100}$
$\mathit{S}.\mathit{I}=2700\times 10\times 2.5∕100=675$
$\therefore$ The Correct answer is Option (1): Rs. 675