COMEDK Exam 2022 Solved Paper

In general, nth mode of a string fixed at ends has frequency,
v=

nv

2l

where, n=1,2,3,......
where, v is the velocity of wave and l is the length of string.
In fourth normal mode, n=4
v=

4v

2l

Given, v=500HZ,l=2m
Hence, 500=

4v

2×2

or, v=

500×4

4

=500m∕s