COMEDK Exam 2022 Solved Paper

If we differenciate the equation of motion,
x=1−t−t2w.x.t. time, we get velocity.
v=

dx

dt

=−1−2t
Comparing with v=u+at, we have u=−1ms−1 and
a=−2ms−2
At t=0,x=1m. Then, u and a both are negative.
Hence, x-coordinate of particle will go on decreasing.