COMEDK Exam 2022 Solved Paper

Let the velocity of the bullet before collision be v, then according to law of conservation of linear momentum,
mv=(m+M)v′ ............(i)
As the mass m of the bullet gets embedded in the wall, hence velocity of bullet + target just after collision will be same,

1

2

(M+m)v′2=(m+M)gn
⇒ v′=√2gh
Putting the value of v' in Eq.(i), we get
⇒ v=√2gh

(m+M)

m

=√2gh(1+

M

m

)