Calculate the molar conductance of 0.025 {\M} aqueous solution of calcium chloride at 25^{\circ} {\C}. The specific conductance of calcium chloride is 12.04 \times 10^{-2} {\Sm}^{-1}

Correct Answer is : 481.6×10−5Sm2mol−1

4.816 \times 10^{-5} {\Sm}^2 {\mol}^{-1}

3.816 \times 10^{-5} {\Sm}^2 {\mol}^{-1}

381.6 \times 10^{-5} {\Sm}^2 {\mol}^{-1}

481.6 \times 10^{-5} {\Sm}^2 {\mol}^{-1}

COMEDK Exam 2022 Solved Paper

Question : 111 of 180

Marks: +1, -0

Calculate the molar conductance of 0.025M aqueous solution of calcium chloride at 25∘C. The specific conductance of calcium chloride is 12.04×10−2Sm−1

4.816×10−5Sm2mol−1
3.816×10−5Sm2mol−1
381.6×10−5Sm2mol−1
481.6×10−5Sm2mol−1

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