COMEDK Exam 2022 Solved Paper

As, K=

1

2

mv2
⇒ K=

1

2

mp2
⇒ p2=2mK
⇒ p=√2mK
Suppose, p1 is the momentum of the body and K1= kinetic energy of the body initially. As the kinetic enery of the body is increased by 300%, new kinetic energy of the body =K1+3K1
Hence, percentage change in momentum
=

p2−p1

p1

×100
=

√2mK2−√2mK1

√2mK1

×100
=

√2m√K2−√K1

√2m√K1

×100
=

√K1+3K1−√K1

√K1

×100

√4K1−√K1

√K1

×100=100%