COMEDK Exam 2019 Solved Paper

Given, capacitance of bigger drop =1µF
Let R be the radius of bigger drop and r be the radius of smaller drops.
According to the question, ‌

4

3

πR3=8×‌

4

3

πr3
⇒R3‌=8r3
⇒R‌=2r
The capacitance of bigger drop ,
C‌=4πε0R
‌=2×4πε0r‌‌(∵R=2r)
Capacitance of smaller drop, C′=4πε0r
Thus, ‌C′=‌

C

2

Hence, ‌C′=‌

1

2

µF