COMEDK Exam 2019 Solved Paper

Given, resistance of the galvanometer, G=40Ω
Current in the galvanometer,
Ig=10mA=10×10−3A
Maximum reading of voltmeter, V=50V
The galvanometer can be converted into voltmeter by connecting a shunt resistance (S) in the series.
Voltage in the voltmeter is given by
‌V=Ig(G+R)
‌∴‌‌50=10×10−3(40+R)
‌⇒‌‌5000=40+R
‌⇒‌‌R=4960Ω
‌