COMEDK Exam 2019 Solved Paper

EMF induced in circular coil of self-inductance L is given by ε=−L‌

dI

dt

EMF is equal to the potential difference dimensionally.
Hence, ‌ε=V
We know, ‌V=‌

W

q

Thus, dimensional formula of potential difference is given as
V‌=‌

[M1L2T−2]

[AT]

‌=[M1L2T−3A−1]
The self-inductance is given by, L=V×‌

dt

dI

Dimensional formula of self-inductance is given by,
L=[M1L2T−3A−1]×‌

[T]

[A]

Dimensional formula of self-inductance,
L=[M1L2T−2A−2]