COMEDK Exam 2019 Solved Paper

Given, resistance of the wire, R=6Ω
When it is cut in two equal parts, then resistance of the each part of wire is given by
r=‌

R

2

=3Ω‌‌(∵R∝l)
Now, these new resistances are connected in parallel combination. The equivalent resistance is given by
‌

1

Req

‌=‌

1

r

+‌

1

r

⇒‌‌‌

1

Req

‌=‌

1

3

+‌

1

3

=‌

2

3

⇒‌‌Req‌=15Ω