COMEDK Exam 2019 Solved Paper

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Question : 165 of 180

Marks: +1, -0

∫‌

sin‌x‌cos‌x

√1−sin‌4x

‌dx=

‌
1
2
sin‌−1(sin‌2x)+C
‌
1
2
cos−1(sin‌2x)+C
tan−1(sin‌2x)+C
tan−1(2sin‌x)+C

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