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Question : 134 of 180
Marks:
+1,
-0
Solution:
We have,
‌=‌+‌+‌+...+‌| 1 |
| [(2+(n−1)3)][5+(n−1)3] |
‌=‌+‌+‌+...+‌‌=‌[‌+‌+‌+...+‌]‌=‌[‌+‌+‌+...+‌| (3n+2)−(3n−1) |
| (3n−1)(3n+2) |
]‌=‌[‌−‌+‌−‌+‌−‌+...+‌−‌]‌=‌[‌−‌]=‌[‌]=‌
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