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Question : 132 of 180
Marks:
+1,
-0
Solution:
(a) When
x=−4, then
4(−4)+3y=20⇒y=12But
x=−4∉N∴(−4,12)∉R(b) When
x=5, then
4(5)+3y=20⇒y=0∴(5,0)∉R (c) When
x=3, then
4(3)+3y=20⇒y=∴(3,4)∉R (d) When x=2, then 4(2)+3y=20⇒y=4∴(2,4)∈R
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