COMEDK Exam 2018 Solved Paper

Redrawing the given circuit network asEquivalent resistance between points D and C,
RDC=‌

(15+15)×15

(15+15)+15

=‌

30×15

45

=10Ω
Similarly, ‌‌RAB=RDC=10Ω
Now, circuit, diagram reduces as∴ Equivalent resistance between points A and B is given as
RAB=(15+10+15)|10=40|10‌=‌

40×10

40+10

‌=‌

400

50

=8Ω