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Question : 162 of 180
Marks:
+1,
-0
Solution:
‌ Let ‌‌I=log(tan‌x)‌dx⇒‌‌I=log‌tan(‌−x)‌dx⇒‌‌I=log‌cot‌x‌dx⇒‌‌I=log‌‌dx⇒‌‌I=−log‌tan‌x‌dx⇒‌‌I=−I⇒2I=0⇒I=0
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