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Question : 123 of 180
Marks:
+1,
-0
Solution:
Let
a=−2+,b=+−2 and
c=−+2+Now,
b×c=||=5++3Now,
a×(b×c)=||=−8+7+11Now, any vector perpendicular to
a and lying in the plane containing
+−2 and
−+2+ is
±(a×(b×c))∴ Required unit vector
=±‌| (−8+7+11) |
| √(−8)2+(7)2+(11)2 |
=±‌
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