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Question : 166 of 180
Marks:
+1,
-0
Solution:
f(x)=1+cos‌2‌x and
f(−x)‌=1+cos(−2x)=1+cos‌2‌x=f(x)⇒‌‌f(x)‌=f(−x)Hence,
f(x) is even function.
⇒=2‌‌‌=2‌‌‌=2‌‌ sec2x‌dx‌=[tan‌x]0π∕4=(tan‌−tan‌0)=1
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