The modulus of [1-\cos \theta+i \sin \theta]^{-1} is

Correct Answer is : 12|cosecθ2|

\frac{1}{2} {\cosec} \frac{\theta}{2}

\frac{1}{2}{| {\cosec} \frac{\theta}{2} |}

{| {\cosec} \frac{\theta}{2} |}

COMEDK Exam 2017 Solved Paper

Question : 134 of 180

Marks: +1, -0

The modulus of [1−cos‌θ+isin‌θ]−1 is

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