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Question : 132 of 180
Marks:
+1,
-0
Solution:
We have,
z‌=reiθ=r(cos‌θ+isin‌θ)
∴‌‌iz‌=ir(cos‌θ+isin‌θ)
‌=ir‌cos‌θ+i2rsin‌θ=−rsin‌θ+ir‌cos‌θ
|eiz|‌=|e(−rsin‌θ+ir‌cos‌θ)|
‌=|e−rsin‌θ|⋅|ir‌cos‌θ|
‌=e−rsin‌θ[√cos2(r‌cos‌θ)+sin‌2(r‌cos‌θ)]
‌=e−rsin‌θ×1=e−rsin‌θ
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