=1,a>b Let e and e′ be the eccentricities of the ellipse and hyperbola. So, e=√‌
a2−b2
a2
=√‌
25−16
25
=‌
3
5
and e′=√‌
a2+b2
a2
=√‌
25+16
25
=‌
√41
5
(i) Centre of ellipse (0,0) and centre of hyperbola is (0,0) (ii) Foci of ellipse are (±ae,0) or (±3,0). Foci of hyperbola are (±ae′,o) or (±√41,0). (iii) Direction of ellipse are x=±‌
a
e
⇒x=±‌
25
3
and directrices of hyperbola are x=±‌
a
e
⇒‌‌x=±‌
25
√41
(iv) Vertices of ellipse are (±a,0) or (±5,0). Vertices of hyperbola are (±a,0) or (±5,0). From the above discussions, their are common is centre and vertices.