x=4(1+\cos \theta) and y=3(1+ \sin \theta) are the parametric equations of

Correct Answer is : (x−4)216+(y−3)29=1

\frac{(x-4)^2}{16}+\frac{(y-3)^2}{9}=1

\frac{(x-4)^2}{16}-\frac{(y-3)^2}{9}=1

\frac{(x+4)^2}{16}+\frac{(y+3)^2}{9}=1

\frac{(x-3)^2}{9}+\frac{(y-4)^2}{16}=1

COMEDK Exam 2016 Solved Paper

Question : 151 of 180

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x=4(1+cos‌θ) and y=3(1+sin‌θ) are the parametric equations of

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