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Question : 143 of 180
Marks:
+1,
-0
Solution:
‌‌ ‌L1:‌=‌=‌‌L2:‌=‌=‌‌Shortest distance between two lines
=|‌|| x2−x1 | y2−y1 | z2−z1 | | a1 | b1 | c1 | | a2 | b2 | c2 |
| |
| √(b1c2−b2c1)2+(c1a2−c2a1)2+(a1b2−a2b1)2 |
| =‌|| −3−3 | −7−8 | 6−3 | | 3 | −1 | 1 | | −3 | 2 | 4 |
| |
| √(−4−2)2+(−3−12)2+(6−3)2 |
=|‌| || |
| √(−6)2+(−15)2+(3)2 |
| On expanding the determinant along
C3.
‌=‌| 3(6−3)−1(−12−45)+4(6+45) |
| √36+225+9 |
‌=‌=‌=√270=3√30\‌
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