The molar conductivities of {\NaOH}, {\NaCl} and {\BaCl}_2 at infinite dilution are 2.481 \times 10^{-2} {\S} {\m}^2 {\mol}^{-1} 1.265 \times 10^{-2} {\S} {\m}^2 {\mol}^{-1} and 2.800 \times 10^{-2} {\S} {\m}^2 {\mol}^{-1} respectively. The molar conductivity of {\Ba}( {\OH})_2 at infinite dilution will be

Correct Answer is : 5.232×10−2 sm2mol−1

5.232 \times 10^{-2} { s} {\m}^2 {\mol}^{-1}

9.654 \times 10^{-2} {\S} {\m}^2 {\mol}^{-1}

4.016 \times 10^{-2} {\S} {\m}^2 {\mol}^{-1}

1.145 \times 10^{-2} {\Sm}^2 {\mol}^{-1}

COMEDK Exam 2014 Solved Paper

Question : 92 of 180

Marks: +1, -0

The molar conductivities of NaOH,NaCl and BaCl2 at infinite dilution are 2.481×10−2Sm2mol−1
1.265×10−2Sm2mol−1 and
2.800×10−2Sm2mol−1 respectively. The molar conductivity of Ba(OH)2 at infinite dilution will be

5.232×10−2 sm2mol−1
9.654×10−2Sm2mol−1
4.016×10−2Sm2mol−1
1.145×10−2Sm2mol−1

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