COMEDK Exam 2014 Solved Paper

d=1.25g∕mL, conc. of solution =3M
= 3 moles in one litre of the situation.
Molar mass of NaCl=23+35.5=58.5gmol−1
Volume of solution =1L=1000mL
Mass of solution =d×V
=1.25gmL−1×1000mL=1250g
Mass of solute (NaCl)=n×molar‌mass
=3×58.5=175.5g
Mass of solvent = mass of solution − mass of solute
=1250−175.5=10745g