COMEDK Exam 2014 Solved Paper

The given situation is shown below

Let P be the location of centre of mass.If x1 and x2 be the distances of the centre of mass P from the two bodies of mass M and m(M>m) respectively, then
Mx1=mc2
⇒

x1

x2

=

m

M

Since, M>m
∴

x1

x2

<1
⇒ $x_1 Thus, position of centre of mass is closer to the heavier body.