Mass of the monkey, m=40kg Maximum tension that the rope can bear, Tmax=600N In option (a), acceleration of monkey, a=6m∕s2 (upward) ∴ By equation of motion, T−mg=ma ⇒ T=m(g+a) =40(10+6)=640N Since, T>Tmax, hence in this case, rope will break. Therefore, option (a) is correct. In option (b), acceleration of monkey, a=4 m\/s^2 (downward) ∴ By equation of motion, T=m(g−a)=40(10−4)=240N Since, $T In option (c), monkey climbs up the uniform speed, v=5m∕s ∴ Acceleration, a=0m∕s2 Hence, by equation of motion, T=mg =40×10=400N Since, $T∴T=m(g−a)=m(g−g)=0.N Since, $T Therefore, only option (a) is correct.