COMEDK Exam 2014 Solved Paper

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Question : 128 of 180

Marks: +1, -0

.If sin‌(120−A)=sin‌(120−B) and 0<A,B<π then all values of A and B are given by

A+B=‌
π
3
A=B or A+B=‌
π
3
A=B
A+B=0

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