COMEDK Exam 2013 Solved Paper

As it is a balanced Wheatstone bridge, so C and D are same potential and the capacitor 2µF is ineffective.
The 3µF and 6µF in upper portion are in series, so equivalent capacitance,
C1=

3×6

3+6

=

18

9

=2µF
Similarly, C2=

4×8

4+8

=

32

12

=

8

3

µF
C1 and C2 are in parallel, so their equivalent capacitance
C=C1+C2=2+

8

3

=

14

3

µF