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COMEDK Exam 2013 Solved Paper
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© examsiri.com
Question :
157 of 180
Marks:
+1
,
-0
∫
‌
d
x
x
(
x
7
+
1
)
is equal to
log
(
‌
x
7
x
7
+
1
)
+
c
‌
1
7
‌
log
(
‌
x
7
x
7
+
1
)
+
c
log
(
‌
x
7
+
1
x
7
)
+
c
‌
1
7
‌
log
(
‌
x
7
+
1
x
7
)
+
c
Validate
Solution:
Let
I
=
∫
1
x
(
x
7
+
1
)
d
x
=
∫
x
6
x
7
(
x
7
+
1
)
d
x
Put
x
7
=
t
⇒
7
x
6
d
x
=
d
t
∴
l
=
1
7
‌
∫
d
t
(
t
+
1
)
=
1
7
‌
∫
(
1
t
−
1
t
+
t
)
d
t
=
1
7
[
logt
−
log
(
t
+
1
)
]
+
c
=
1
7
‌
log
(
t
t
+
1
)
+
c
=
1
7
‌
log
(
x
7
x
7
+
1
)
+
c
© examsiri.com
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