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Question : 140 of 180
Marks:
+1,
-0
Solution:
Let
I=∫0dx..........(i) =∫0| cos(−x)−sin(−x) |
| 1+cos(−x)sin(−x) |
dx [∵∫0af(x)dx=∫0af(a−x)dx] ∴l=∫0dx................(ii) On adding Eqs. (i) and (ii), we get
2l=−⇒I=0
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