Inverse of the matrix \left[\begin{array}{cc}\cos 2 \theta & - \sin \\\2 \theta \ \sin \\\2 \theta & \cos 2 \theta]\end{array} is

Correct Answer is : [cos29sin29−sin2θcos2θ]

\left[\begin{array}{cc}\cos 2 \theta & - \sin \\\2 \theta \ \sin \\\2 \theta & \cos 2 \theta]\end{array}

\left[\begin{array}{cc}\cos 2 \theta & \sin \\\2 \theta \ \sin \\\2 \theta & -\cos 2 \theta]\end{array}

\left[\begin{array}{cc}\cos 2 \theta & \sin \\\2 \theta \ \sin \\\2 \theta & \cos 2 \theta]\end{array}

\left[\begin{array}{cc}\cos 29 & \sin \\\29 \ - \sin \\\2 \theta & \cos 2 \theta]\end{array}

COMEDK Exam 2013 Solved Paper

Question : 127 of 180

Marks: +1, -0

Inverse of the matrix [

cos‌2‌θ	−sin‌2θ
sin‌2θ	cos‌2‌θ

] is

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cos‌29	sin‌29
−sin‌2θ	cos‌2‌θ

cos2θ	−sin2θ
sin2θ	cos2θ

cos2θ	−sin2θ
sin2θ	cos2θ

cos2θ	sin2θ
−sin2θ	cos2θ