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Question : 84 of 180
Marks:
+1,
-0
Solution:
Number of moles of
CaCO3== =0.01mol ∴ Molar mass of
CaCO3=10gmol−1 100mL‌of‌‌H‌C‌l=×=0.02mol The reaction is
+⟶CaCl2+CO2+H2O ∴0.01 mole of
CaCO3 reacts with
0.02 mole of
HCl.
∴ Both are completely consumed in the given reaction.
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