COMEDK 2024 Shift 2 Paper

The area of a triangle with vertices (x1,y1),(x2,y2) and (x3,y3) is given by:
‌

1

2

|

x1	y1	1
x2	y2	1
x3	y3	1

|
Substituting the given vertices into the formula, we have:
35=‌

1

2

|

−2	a	1
2	−6	1
5	4	1

|
Expanding the determinant, we get:

Simplifying the equation, we get:
‌35=‌

1

2

(12+5a+8+30−2a+8)
‌35=‌

1

2

(58+3a)
‌70=58+3a
‌12=3a
‌a=‌

12

3

=4
Therefore, the value of a is 4 . So the answer is Option A.