The permanganate ion in acid medium acts as an oxidant and gets converted to its lower oxidation state. What would be the spin only magnetic moment of such reduced manganese ion?
In order to find the spin-only magnetic moment of the reduced manganese ion, we need to follow a stepby-step process to determine the oxidation states and then compute the magnetic moment. 1. The permanganate ion (MnO4−)has manganese in the +7 oxidation state. In an acidic medium, it typically gets reduced to Mn2+. 2. To find the magnetic moment, we first need to determine the number of unpaired electrons in the Mn2+ ion. Manganese in its elemental form has the electron configuration [Ar]3d54s2. 3. For Mn2+, the ion will lose two electrons from the 4s orbital, giving it the electron configuration [Ar]3d5. This configuration represents 5 unpaired electrons. 4. The spin-only magnetic moment is given by the formula:
µ=√n(n+2)‌BM where n is the number of unpaired electrons. 5. Substituting n=5 for Mn2+ : µ=√5(5+2)=√35‌BM 6. Calculate the value: µ=√35≈5.92‌BM Therefore, the spin-only magnetic moment of the reduced manganese ion in the Mn2+ state is approximately 5.92 BM , which corresponds to option D.