The number in question, 25×36×52, is a product of prime factors. We want to find how many of its factors are perfect squares. A number is a perfect square if all the exponents in its prime factorization are even. Let's consider the general form of a factor of the number, which can be written as: 2a×3b×5c Here, a,b, and c are integers that satisfy the conditions: ‌0≤a≤5 ‌0≤b≤6 ‌0≤c≤2 a can be 0,2 , or 4 - giving us 3 choices. b can be 0,2,4, or 6 - giving us 4 choices. c can be 0 or 2 - giving us 2 choices. The total number of perfect square factors is the product of the choices for a,b, and c : Total perfect square factors =3×4×2=24 Therefore, the answer is Option B: 24. For this factor to be a perfect square, each of a,b, and c must be even. Thus: