If \cos \alpha=k \cos \beta then \cot (\frac{\alpha+\beta}{2}) is equal to

Correct Answer is : k+1k−1tan(β−α2)

\frac{k+1}{k-1} \tan (\frac{\alpha-\beta}{2})

\frac{k+1}{k-1} \tan (\frac{\beta-\alpha}{2})

\frac{k-1}{k+1} \tan (\frac{\beta-\alpha}{2})

\frac{k-1}{k+1} \tan (\frac{\alpha-\beta}{2})

COMEDK 2023 Shift 1 Paper

Question : 106 of 180

Marks: +1, -0

If cos‌α=k‌cos‌β then cot(‌

α+β

) is equal to

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